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x=133(3)/2 x=139/2 x=4/2 x=2 Therefore we have x=2 and y=3 New questions in Math sabki aatma ko shanti dilaakaraap akele yaha kya karoge???XD don't take it seriously she is a girl and we are just jokingquestionwhat is metabolism how to maintain it?Simplify ( (3x^ (3/2)y^3)/ (x^2y^ (1/2)))^2 (3x3 2y3 x2y 1 2) 2 ( 3 x 3 2 y 3 x 2 y − 1 2) − 2 Move x3 2 x 3 2 to the denominator using the negative exponent rule bn = 1 b n b n = 1 b − n ( 3y3 x2y 1 2x 3 2) 2Factoriser x^25x4 x2 5x 4 x 2 5 x 4 Considérer la forme x2 bxc x 2 b x c Trouver deux entiers dont le produit vaut c c et dont la somme vaut b b Dans notre cas, dont le produit vaut 4 4 et dont la somme vaut 5 5 1,4 1, 4 Écrire la forme factorisée avec ces entiers (x1)(x 4) ( x 1) (




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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more Given as (2/x) – (3/y) (3/z) = 10 (1/x) (1/y) (1/z) = 10 (3/x) – (1/y) (2/z) = 13 The given equation can be written in matrix form = 5(4 – 6) – 3(8 – 3) 1(4 – 2) = – 10 – 15 3 = – 22 So, the above system has a unique solution, given by X = A – 1 B Cofactors of A are C 11 = (– 1) 1 1 (4 – 6) = – 2 C 21 = (– 1) 2 1 (12 – 2) = – 10 C 31 = (� Mathématiques du collège et du lycée x^ (3/2) Affichage des résultats 1 à 3 sur 3



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